45x^2-62x-16=0

Solution for 45x^2-62x-16=0 equation:

45x^2-62x-16=0

a = 45; b = -62; c = -16;
Δ = b2-4ac
Δ = -622-4·45·(-16)
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6724}=82$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-82}{2*45}=\frac{-20}{90}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+82}{2*45}=\frac{144}{90}
=1+3/5
$